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NS: Branko Krolo - Aljoša Čakić (Goran Čekol - Vedran Zorić 13-24) EW: Jasminka Pojer - Tatjana Mirković |
NS: Ante Vilić - Žarko Čokljat
EW: Goran Čekol - Vedran Zorić (Aljoša Čakić - Branko Krolo 13-24) |
IMP | ||||||||||||
| board | kontrakt | by | ataka | št. | rez | But | kontrakt | by | ataka | št. | rez | But | NS | EW |
| 1. | 4 ♠ | N | ♠9 | = | 420 | 1 | 3 ♠ | N | ♦2 | +1 | 170 | -6 | 6 | |
| 2. | 3 NT | N | ♦8 | +1 | 630 | -1 | 3 NT | S | ♠7 | +2 | 660 | 1 | ||
| 3. | 2 ♥ | S | ♠3 | +2 | 170 | 1 | 3 ♦ | S | ♣K | -2 | -100 | -6 | 7 | |
| 4. | 6 ♣ | S | ♥A | -2 | -200 | -10 | 5 ♠ | N | ♥K | -2 | -200 | -10 | ||
| 5. | 3 NT | N | ♥7 | = | 600 | 11 | 3 ♥ | E | ♣A | +1 | -170 | -6 | 13 | |
| 6. | 3 ♥ | E | ♣5 | = | -140 | 4 | 4 ♥ x | E | ♣5 | = | -790 | -10 | 12 | |
| 7. | 2 NT | S | ♦2 | = | 120 | 3 | 3 ♣ | S | ♣3 | = | 110 | 3 | ||
| 8. | 2 ♦ | W | ♥2 | +3 | -150 | -2 | 3 ♥ x | N | ♦4 | -3 | -500 | -9 | 8 | |
| 9. | 4 ♥ | N | ♣9 | = | 420 | 1 | 4 ♥ | N | ♦K | +1 | 450 | 2 | 1 | |
| 10. | 2 NT | S | ♠5 | +1 | 150 | 5 | 2 NT | S | ♠9 | -1 | -100 | -1 | 6 | |
| 11. | 4 ♥ x | E | ♠A | -1 | 100 | 1 | PASS | N | 0 | -2 | 3 | |||
| 12. | 3 NT | N | ♦Q | +1 | 630 | 3 NT | N | ♦Q | +2 | 660 | 1 | 1 | ||
| 13. | 4 ♣ | E | ♠6 | -1 | 100 | 3 | 1 ♠ | N | ♦J | +1 | 110 | 4 | ||
| 14. | 4 ♥ | N | ♣4 | = | 420 | 1 | 3 NT | S | ♦3 | = | 400 | 1 | 1 | |
| 15. | 6 ♠ | S | ♣2 | = | 1430 | 2 | 6 ♠ | S | ♣2 | = | 1430 | 2 | ||
| 16. | 4 ♠ x | N | ♣8 | +1 | 690 | 11 | 4 ♠ | N | ♦Q | = | 420 | 7 | 7 | |
| 17. | 2 NT | W | ♥K | -2 | 100 | 3 ♠ | E | ♥7 | -1 | 50 | -2 | 2 | ||
| 18. | 6 ♣ | N | ♣4 | = | 1370 | 10 | 3 NT | S | ♠5 | +1 | 630 | -7 | 12 | |
| 19. | 4 ♠ x | N | ♣A | -2 | -300 | -6 | 4 ♠ | S | ♦10 | -2 | -100 | -1 | 5 | |
| 20. | 4 ♥ | N | ♠A | -1 | -100 | 2 | 3 ♥ | S | ♠7 | -1 | -100 | 2 | ||
| 21. | 3 NT | N | ♦Q | +1 | 630 | 12 | 3 NT | N | ♥3 | -2 | -200 | -6 | 13 | |
| 22. | 4 ♠ | N | ♠9 | = | 420 | 6 | 2 NT | N | ♠9 | -1 | -50 | -6 | 10 | |
| 23. | 2 ♥ | W | ♦Q | = | -110 | 3 ♥ | W | ♣J | = | -140 | -1 | 1 | ||
| 24. | 1 NT | N | ♠3 | = | 90 | 2 | 1 NT | N | ♠3 | -1 | -50 | -2 | 4 | |
| ∑ | 57 | -53 | 105 | 8 | ||||||||||